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Bingel [31]
3 years ago
8

I'm not sure how to solve this... Could anyone please help me?

Mathematics
1 answer:
Mumz [18]3 years ago
5 0

Answer:

the last one 2x-⁴y⁶

Step-by-step explanation:

-4 : - 2 = 2

x-³ : x = x-³-¹ = x-⁴

y⁴ : y-² = y⁴-(-²) = y⁴+² = y⁶

final

2x-⁴y⁶

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Complete the solution of the equation. Find the value of y when x equals -4 <br> x + 3y = 14
NeX [460]
Move all terms that don't contain y to the right side and solve.
y = - x/3 + 14/3
Hope this helps! :)
6 0
3 years ago
I do not understand!!help please?!
blsea [12.9K]

Answer:

a. (3x^4 + 6 ) + (2x^2)

b. (X^3 ) + (-x -7)

c. (4.6x^4) + (-1.5x^2)

Step-by-step explanation:

For the first one, we have to write to polynomials, which equal 3x^4 + 2x^2 +6

One possible solution is (3x^4 + 6 ) + (2x^2)

For b, we can do,

(X^3 ) + (-x -7)

And finally for c, we can write,

(4.6x^4) + (-1.5x^2)

5 0
3 years ago
What is 96 Is 12 percent identify the part whole and percent​
n200080 [17]
96 times .12 is the percent
6 0
3 years ago
The length of the carpet is 8 yards 9 inches.
zzz [600]

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7 0
3 years ago
Read 2 more answers
The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27
Naddik [55]
ANSWER
3\pi sq.\: in.

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

R:r=3:1

We can rewrite it as fractions to get,

\frac{R}{r} = \frac{3}{1}

We make R the subject to get,

R = 3r

The area of the bigger circle can be found using the formula,

Area=\pi {r}^{2}

This implies that,

Area=\pi ({3r})^{2}

Area=9\pi {r}^{2}

But it was given in the question that, the area of the bigger circle is 27π.

27\pi=9\pi {r}^{2}

We divide through by 9π to get,

3 = {r}^{2}

This means that,
r = \sqrt{3}

The area of the smaller circle is therefore

= \pi {( \sqrt{3}) }^{2}

= 3\pi
8 0
3 years ago
Read 2 more answers
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