4.06 Question 1
1 answer:
Answer:
Answer:
The points which represents a the solution are: <u>A, C, D and K</u>
<u>Step-by-step explanation:</u>
See the attached figure.
The given inequalities: y ≤ −2x + 10 & y > 1/(2x − 2)
The given inequalities: y ≤ −2x + 10 & y > 1/(2x − 2)The given points: A(-5,4), B(4,7), C(-2,7), D(-7,1), E(4,-2),
The given inequalities: y ≤ −2x + 10 & y > 1/(2x − 2)The given points: A(-5,4), B(4,7), C(-2,7), D(-7,1), E(4,-2), F(1,-6), G(-3,-10), H(-4,-4), I(9,3), J(7,-4) and K(2,3).
The attached figure represents the graph of the given inequalities.
The shaded area represents the solution of the inequalities.
So, the points lies in the shaded area represents the solution of the inequalities.
So, points A, C, D and K are a solution to the system of inequalities.
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<u>Note:</u>
If the given inequalities: y ≤ −2x + 10 & y > (1/2x) - 2
It will be the same solution.
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Answer:
Money owned by Steve = $11
Money owned by Ben = $13
Step-by-step explanation:
Let x denotes the money owned by Steve and y denotes the money owned by Ben.
Then, Steve gives $3 to Ben
Money left with Steve = x-3 and Ben = y+3
Now, Ben will have twice as much as Steve.
⇒ y+3 = 2(x-3) .............(1)
If Ben gives Steve $7
Money left with Steve = x+7 and Ben = y-7
Then, the amount Ben has will be one-third that of Steve’s.
⇒ y-7 = (x+7) ..........(2)
Solving equation (1) and (2) by elimination method, we get
x = 11 and y = 13
⇒ Money owned by Steve = $11
Money owned by Ben = $13