I think it is A as solid atoms are close and gases are far away
<span>Out of the possible answers for this question, fluorine in the second period is correct. Of the four elements fluorine, chlorine, bromine and iodine, fluorine has the largest first ionization energy, with a Enthalpy number of 1681.0. Of all the elements, helium has the highest first ionization energy figure.</span>
Answer:
B.) an intensive property
Explanation:
Bc it is a Characteristic Property that won't change no matter what size of sample is tested
Due to electronegativity difference between H and F atom.
<h3>
What is the reason for the difference ?</h3>
- The bond length of HF is 92 pm. It is 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm).
- The shorter of the bond length is due to the difference in electronegativity between H and F atom. The electronegativity of F is 4.0, whereas the electronegativity of H is 2.1.
- Greater the difference of electronegativity between the bonded atoms, shorter will be the bond length.
- As becomes smaller i.e. as we proceed from HF to HI, this effect becomes lessens and bond length will be more predictable.
Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.
Learn more about bond length here :
brainly.com/question/13683866
#SPJ4
I don't know much about this, but probably the reason why your teacher circled 300k is because of what's in the photo below. If you couldn't tell from the photo, its because 300k isn't negative. Anyway this is my guess, based on my limited knowledge.
