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3 years ago

What is 8÷39.2 help me please

Chemistry

1 answer:

svet-max [94.6K]3 years ago

5 0

0.2040816327
rounded=0.20

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At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106

lana [24]

Answer:

The new equilibrium concentration of HI: [HI] = 3.589 M

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

Given chemical reaction: H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant ( $K_{c}$ ) for the given chemical reaction, is given by the equation:

$K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}$

At the original equilibrium state:

$K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}$

$K_{c} = \frac {1.6641}{0.002332} = 713.59$

Therefore, at the new equilibrium state:

$K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}$

$\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}$

$\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88$

$\Rightarrow [HI] = \sqrt {12.88} = 3.589 M$

Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M

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2 years ago

Balance the following

olga55 [171]

Answer:

Your coefficients (the numbers in front of the molecule) will be the following from left to right.

1. 1 - 2 - 1 - 2

2. 2 - 1 - 2 - 2 - 1

3. 2 - 4 - 1

4. 2 - 4 - 3

5. 2 - 2 - 2 - 1

6. 1 - 1 - 1

7. 2 - 1 - 2

8. 3 - 1 - 2 - 3

9. 3 - 1 - 2 - 3

10. 2 - 1 - 1 - 1

Explanation:

To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.

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1 year ago

Will made a cup of hot tea and placed it on the tableA few minutes later, he picked up the cup and touched the warm table where

aliina [53]

D. Because convection is the transfer of heat and because the heat from the cup was transferred on to the table it has to be d :)

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3 years ago

For the reaction x2 + y + z → xy + xz, it is found that doubling the concentration of x2 doubles the reaction rate, tripling the

andre [41]

R=[x2][y] rate law of the reaction
check:
if we double x2, r(new) =[2*x2][y]=2*[x2]*[y]=2*r
if we triple y, r(new) =[x2][3y]=3*[x2]*[y]=3*r
z- no effect, so z is not included

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3 years ago

Read 2 more answers

Select the correct answer.

Finger [1]

Answer:

D.2NaBr+CaF 2NaF CaBr2

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