1st Define Covalent bond and it's type
1 answer:
Answer:
- COVELENT BOND:-The chemical bond formed by the sharing of an electron pair between two atoms so that both the atoms get their octet complete is called covalent bond
- SINGLE COVELENT BOND:-it is formed by sharing of one pair of electron between two atoms
- DOUBLE COVELENT BOND:-it is formed by sharing of two pair of electron between two atoms
- TRIPLE COVELENT BOND:- it us formed by sharing of three pair of electron beyween two atoms
2)Electron dot structures of carbon dioxide:-Oxygen atom contains 6 valence electrons which form 2 lone pairs. Since it is bonded to only one carbon atom, it must form a double bond. Carbon atom contains four valence electrons, resulting in zero lone pairs. Therefore, it is doubly bonded to each oxygen atom.
3))Sulfur has an atomic number is 16 with the
symbol as 'S'
- The electronic configuration of sulfur is said to be 2,8,6
- The valence electrons present in sulfur is 6.
- Sulfur forms an octet structure by connecting 8 sulfur atoms with each other by the formation of single covalent bonds.
- The sulfur molecule's chemical formula is S8.
- Sulfur is usually used in the manufacture of sulphuric acid.
Explanation:
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Answer : The volume of consumed are,
L.
Explanation :
The balanced chemical reaction will be:
First we have to calculate the moles of Al.
Molar mass of Al = 27 g/mole
Now we have to calculate the moles of .
From the reaction we conclude that,
As, 4 mole of Al react with 3 moles of
So, 2 mole of Al react with moles of
Now we have to calculate the volume of consumed.
As we know that, 1 mole of substance occupies 22.4 liter volume of gas.
As, 1 mole of occupies 22.4 liter volume of
gas
So, mole of
occupies
liter volume of
gas
Therefore, the volume of consumed are,
L.
Answer: The correct answer is: " 0.54 g " .
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Explanation:
Note that "hydrogen gas" is:
H₂ (g) ; that is: a "diatomic element" (diatomic gas) ;
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The molecular weight of "H" is: 1.00794 g ;
(From the Periodic Table of Elements).
So, the molecular weight of: H₂ (g) is:
" 1.00794 g * 2 = 2.01588 g ; {use calculator) ;
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Note the conversion for a gas at STP:
______
1 mol of a gas = 22.4 L gas;
___
i.e. " 1 mol / 22.4 L " ;
____
So: " 5.7 L H₂ (g)
The "L" ("literes" cancel out to "1" ; since "L/L = 1 ;
The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;
____
and we are left with:
____
[5.7 * 2.104588 g ] / 22.4 = ? g ;
______________________
→ [ 11.9961516 g ] / 22.4 =
0.53554248214 g ;l
_____________________________
We round this value to: " 0.54 g " ;
→ since "5.7 L " has 2 (two) significant figures;
22.4 is an exact number conversion;
and "5.7 L" has fewer significant figures than:
" 2.104588 " ; or: " 1.00794 " .
→ as such: We round to "2 (two) significant figures."
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Answer:
Explanation:
Given that:
The distillation is carried out at a pressure of 1 atm
The feed harbors 25% mole of methanol (z)
The total moles of feed is usually 100 moles
In the system, we have both methanol and water
Using the total mole balance for the distillation column.
Fz = Lx + Vy
where;
F = amount of feed
z = mole fraction of ethanol (in feed)
L = amount of liquid product out of the column
V = amount of vapor product out of the column
x = mole fraction of methanol out of the liquid
y = mole fraction of methanol out of the vapor.
SO;
(a)
If all the feed is vaporized, then the vapor will likely have the same composition as the feed.
(b)
If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.
(c)
If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.
The balance equation would be:
Replacing z = 0.25; we have:
0.75 = 2x + y
(d)
If 2/3 of the feed is vaporized;
Then:
replacing z = 0.25
0.75 = x + 2y