Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
What exactly are you asking. Are you asking for area or perimeter?
This would just be 7 1/5 + 3/5 since the negative sign gets distributed and makes (-3/5) into a positive number.
From there you have basic math and you get 7 4/5.
Um -1/3(24+3)-1 = -10
So -10 is the answer