Given:
n = 50, sample size
, sample mean
s = 2.4 min, sample standard deviation.
The confidence interval is
At the 99% confidence level, t* (from the student's t-distribution) is
t* = 2.68
Therefore
t*(s/√n) = 2.68*(2.4/√50) = 0.9096
The confidence interval is
(23.6-0.9096, 23.6+0.9096) ≈ (22.69, 24.51)
Answer: (22.7, 24.5)
Given:
Number of gym members in last quarter = 490
Number of gym members in this quarter = 686
To find:
The percent of increase in the number of members.
Solution:
We have,
Number of gym members in last quarter = 490
Number of gym members in this quarter = 686
Now, the percent of increase in the number of members.
Therefore, the gym members increased by 40%.
Answer:
See explanation
Step-by-step explanation:
Let 
be the number of students and 
be the number of adults on the show.
1. Tickets cost $15 for students, so x student tickets cost $15x.
Tickets cost $25 for adults, so y adult tickets cost $25y.
Total cost of all tickets is $(15x + 25y).
The charity show is conducted in order to raise at least $3,750, thus
2. The auditorium can accommodate up to 180 spectators, hence
3. We get the system of inequalities:
Plot all solutions sets to each inequality and the common region is the solution set to the system of inequalities. This region is not empty, so the charity will reach its goal. For example, if they sell 50 students tickets and 125 adult tickets, they will raise 
