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otez555 [7]
3 years ago
11

A representation of a round object on a flat surface is called a Select one:

Mathematics
1 answer:
postnew [5]3 years ago
3 0

A representation of a round object on a flat surface is called a - projection

Option A is correct.


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Answer:

Where is the function shown below?

Step-by-step explanation:

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What is the median value of the data set shown on the line plot? Enter your answer in the box.
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1/2 of 14 is 7 so 7th x plus 8th x = 30+30 / 2 = the median is 30
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A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

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8 0
2 years ago
a rectangular pyramid has a volume of 190 cubic centimeters. Find two possible sets of measurements for the base area and height
DerKrebs [107]
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>

<em><u>Solution:</u></em>

<em><u>The volume of rectangular pyramid is given as:</u></em>

Volume = \frac{1}{3} \times base\ area \times height

Given that,

<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>

<em><u></u></em>190= \frac{1}{3} \times base\ area \times height<em><u></u></em>

<em><u>Substitute, base area = 570 and height = 1</u></em>

Then we get,

190 = \frac{1}{3} \times 570 \times 1\\\\190 = 190

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively

<em><u>Substitute, base area = 285 and height = 2</u></em>

190 = \frac{1}{3} \times 285 \times 2\\\\190 = \frac{1}{3} \times 570\\\\190 = 190

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively

6 0
3 years ago
26 x 5/12 explain in steps
hoa [83]
First simplify: 26 x 5/12 would equal to 13 x 5/6 because we divided it 2, then do the equation, which would now be 65/6, 13 x 5 and 1 x 6 so now we can make it into mixed numbers, so 10 5/6

ANSWER: 65/6 or 10 5/6
8 0
3 years ago
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