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bagirrra123 [75]
2 years ago
7

Pls help me

Mathematics
1 answer:
deff fn [24]2 years ago
5 0

Answer:

Angle 1: Can be measures of triangle: 84

Cannot be angle measures of triangle: 49, 47

Angle 2: Can be measures of triangle: none

Cannot be angle measures of triangle: 50,89,50

Angle 3: Can be angle measures of triangle: 75, 15, 45

Cannot be angle measures of triangle: none

Angle 4: Can be angle measures of triangle: none

Cannot be angle measures of triangle: 25, 22, 133

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C. The range represents the number of users each month for 36 months.
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ACCTUALLY HELP ME??!!!!!!! NEEDED FOR TOMORROW AND 50 POINTS! will award brainliest for first answer!!
drek231 [11]

Answer:

a:c = 35:24

a:c = 20:27

a:c = 35:22

a:c = 28:27

Step-by-step explanation:

a:b = 7:3

Using cross products

3a = 7b

Divide by 7

3a/7 = b

Now we want

8b = 5c

Substitute in 3a/7 for b

8 (3a/7) = 5c

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Divide by c

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Divide by 24

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a:c = 35:24

a:b = 4:9

Using cross products

9a = 4b

Divide by 4

9a/4 = b

Now we want

3b = 5c

Substitute in 9a/4 for b

3 (9a/4) = 5c

27/4a = 5c

Multiply by 4

27/4a *4 = 5*4c

27a = 20c

Divide by c

27 a/c = 20

Divide by 27

a/c = 20/27

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b:c = 5:11

Using cross products

11b = 5c

Divide by 11

b = 5c/11

Now we want

2a = 7b

Substitute in 5c/11 for b

2a = 7(5c/11)

2a = 35c/11

Multiply by 11

2a*11 = 35c

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Divide by c

22 a/c = 35

Divide by 22

a/c = 35/22

a:c = 35:22

b:c = 14:3

Using cross products

3b = 14c

Divide by 3

b = 14c/3

Now we want

9a = 2b

Substitute in 14c/3 for b

9a = 2(14c/3)

9a = 28c/3

Multiply by 3

9a*3 = 28c

27a = 28c

Divide by c

27 a/c = 28

Divide by 27

a/c = 28/27

a:c = 28:27

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How many different ways are there to rearrange the letters of the word EXAM, if you don't care if the results is a recognizable
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In this case, all letters are unique.

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This is same as 4x3x2x1.

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