All categories

2 years ago

Pls help me

Mathematics

1 answer:

deff fn [24]2 years ago

5 0

Answer:

Angle 1: Can be measures of triangle: 84

Cannot be angle measures of triangle: 49, 47

Angle 2: Can be measures of triangle: none

Cannot be angle measures of triangle: 50,89,50

Angle 3: Can be angle measures of triangle: 75, 15, 45

Cannot be angle measures of triangle: none

Angle 4: Can be angle measures of triangle: none

Cannot be angle measures of triangle: 25, 22, 133

You might be interested in

The local utility company averages rates to determine a standard monthly charge for area businesses. If you are charged $150 for

lisabon 2012 [21]

The average of 3 numbers is their total divided by 3.
(150 +205 +178)/3 ≈ 178.67

Rounded to the nearest dollar, the average charge for the period is $178 per month.

6 0

4 years ago

8 4/5 falls into what catergorie

leonid [27]

A because it isn't a whole number or integer or irrational

6 0

4 years ago

Read 2 more answers

You move right 7 units and left 4 units. You end at (0, -2). Where did you start?

Afina-wow [57]

Answer:

(-3, -2)

Step-by-step explanation:

1. you moved right 7 units

2. you moved left 4 units

3. you ended up in (0, -2)

if you reverse it,

1. you start in (0, -2)

2. you move right 4 units (4, -2)

3. you move left 7 units (-3, -2)

4 0

2 years ago

Read 2 more answers

Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)

xenn [34]

Answer:

$d=\sqrt{73}\approx8.54$

Step-by-step explanation:

So we have the two points (10,-4) and (2,-7).

And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.

1) Distance Formula.

The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:

$d=\sqrt{((2)-(10))+((-7)-(-4))^2$

Simplify:

$d=\sqrt{(2-10)^2+(-7+4)^2$

Subtract:

$d=\sqrt{(-8)^2+(-3)^2$

Square:

$d=\sqrt{64+9}$

Add:

$d=\sqrt{73}$

Approximate:

$d\approx8.54$

So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.

2) Pythagorean Theorem

Please refer to the graph.

So, we want to find the distance. This will be the length of the red line, or the hypotenuse.

First, let's find the length of the two legs.

The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:

$(10-2)=8$

Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.

And the shorter leg is the difference between the two y-coordinates. Namely:

$(-7-(-4))=-3=3$