Ask question

Ask question

All categories

2 years ago

12

You will need 100 feet of fencing to put all the way around a rectangular garden. The length of the garden is 30 feet. What is t

he width?

1 answer:

gregori [183]2 years ago

5 0

Answer:

20 feet

Step-by-step explanation:

100-(2*30)=40

40/2=20

You might be interested in

Describe the steps you used to solve the equation and find the amount of Carrie’s allowance. Linear equation: 1/4 a + 1/3 a + 8

zzz [600]

Answer:24

Step-by-step explanation:

Subtract 8 from 22 = 1/4a+1/3a=14

Add the fractions together =7/12a=14

Divide 14 by 7/12 and a=24

4 0

2 years ago

Read 2 more answers

Giving medal. A new car that sells for $21,000 depreciates (decreases in value) 16% each year. Write a function that models the

Natali5045456 [20]

$21,000-16%
16% of $21,000 is $3,360
$21,000-$3,360=$17,640
1st year would be $17,640

16% of $17,640 is $2,822
$17,640-$2,822 is $14,817
2nd year would be $14,817

16% of $14,817 is $2,370
$14,817-$2,370=$12,446
3rd year would be $12,446

$12,446 rounded would be $12,447

So A) $12,447

Hope this helps out :)

4 0

3 years ago

Read 2 more answers

I will give Brainiest if your right

Setler79 [48]

Answer:

I'm always right B-) SHEESH

5 0

2 years ago

The cargo of the truck weighs less than 2,800 pounds. Use w to represent the weight (in pounds) of the cargo.

MakcuM [25]

Answer:

w < 2,800lb

Step-by-step explanation:

w weighs less than 2,800 pounds.

5 0

2 years ago

Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin

Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

$time=\frac{distance}{speed}$

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

$3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)$

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

$x - 3 = \frac{distance}{80} \\distance = 80(x-3) - - - - - (2)$

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

$50(3+x)=80(x-3)$

$150 +50x=80x-240\\$

Next, collecting like terms:

$150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\$

dividing both sides by 3:

x = 390÷30 = 13

∴ x = 13 minutes

7 0

3 years ago