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Nata [24]
3 years ago
5

Two cars started from the same point, at 10 am, traveling in the same direction at 60 and 90 mph respectively. At what time will

they be 450 miles apart? ( with explanation )
Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0
Alright so 10:00am

90-60=30

450/30=15

15 hours after 10:00am is 1:00am
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Which number line shows the solution to 2/3 x - 5>3 ? PLS I NEED IT FOR RIGHT NOW
nataly862011 [7]

Answer:

<h2>D</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about</h3>
  • inequality
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first note: it will be more easy if we solve the inequality first

so let's solve it together

\frac{2}{3} x - 5 > 3

\frac{2}{3} x > 8

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so what we get

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<h2>so the answer would be d</h2>
6 0
3 years ago
Can anyone help me? plz if you let me know the answer that would be greatly appreciated
Ivahew [28]
I would say choice C with 4 is the right ones
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The fish population in a local stream is decreasing at a rate of 5% per year. The original population was 75,000 fish. What is t
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Step-by-step explanation:

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4 0
3 years ago
A manufacturer makes plastic wrap used in food packaging and aims to have a minimum breaking strength of 0.5 kg. If the mean bre
Darina [25.2K]

Answer:

Option D

Step-by-step explanation:

A type I error occurs when you reject the null hypothesis when it is actually true.

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7 0
3 years ago
If any of the graphs below have a Hamiltonian circuit, list the vertices of the complete circuit. There may be many possibilitie
german

9514 1404 393

Answer:

  1. ABHGEFDCA
  2. does not exist
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Step-by-step explanation:

A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.

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For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.

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For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.

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3 years ago
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