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Paul [167]
3 years ago
8

Complete the table for the relationship shown in the graph

Mathematics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

where ?

Step-by-step explanation:

where is the question to solve ?

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Write an inequality that represents 10 less than a 4 times a number more than 10,000
OLga [1]
10-4×>10,000??? I'm sorry Im not good at math
4 0
3 years ago
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Please help! Two math problems!!!
Fynjy0 [20]

Answer:

Tell me if i am wrong. :)

Step-by-step explanation:

To solve for y:

Q.1   2x + y = -1

       y = -1 - 2x

Q. 2.  4x - 5y = 7

        y = 7 - 4x over -5

 

3 0
3 years ago
HELP!! Select the values for the domain and range of the functions graphed below.
Goryan [66]

Answer:

Graph 1

Domain = -8 =< x =< 10

Range = -9 =< f(x) =< 9

Graph 2

Domain = -1 =< x =< 5

Range = -1 =< f(x) =< 2

Explaination:

Domain means the inputed x values on the x-axis, so to make things simpler and to not write every individual x values. We write it with <, >, and =<. (you can see it as the 'width' of a graph).

Range means the output y values on the y-axis. It's like the 'height' of a graph. And also, to make things simpler and to not write every individual y values. We write it with <, >, and =< with f(x) too because f(x) = y.

3 0
2 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
8,782 divided by 2 can you please explain me the process so i can do it
jenyasd209 [6]

Answer:

4,391

Step-by-step explanation:

next time use a caculator luv <3

5 0
2 years ago
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