Answer:
60 degrees
Step-by-step explanation:
I believe in the triangle it says 57 degrees so if you round 57 to the nearest tenth you get 60 so it would be 60 degrees
Answer:
See Below
Step-by-step explanation:
The surface area of cylinder is given by the formula:

Where
r is radius ( diameter is 4, so radius is 4/2 = 2)
h is height ( h = 9)
Lets find original surface are:

<u>Halving diameter:</u>
diameter would be 4/2 = 2, so radius would be 2/2 = 1
So, SA would be:

<u>Halving height:</u>
Height is 9, halving would make it 9/2 = 4.5
Now, calculating new SA:

Original SA is
,
Halving diameter makes it 
Halving height makes it 
So, halving diameter does not have same effect as halving height.
The boxplot required to answer the questions is attached below :
Answer:
The range for the Kentucky temperature :
(58.3 - 52.2) = 6.1
The range for the Illinois temperature :
(55 - 49.9) = 5.1
The IQR for the Kentucky temperature :
(57.3 - 54.5) = 2.8
The IQR for the Illinois temperature :
(53.3 - 50.9) = 2.4
Step-by-step explanation:
Range = maximum - minimum
Maximum and minimum values are given by the values at the end and start of the whisker.
The range for the Kentucky temperature :
(58.3 - 52.2) = 6.1
The range for the Illinois temperature :
(55 - 49.9) = 5.1
IQR = Q3 - Q1
Q3 = Value at the end of the box
Q1 = value of start of box
The IQR for the Kentucky temperature :
(57.3 - 54.5) = 2.8
The IQR for the Illinois temperature :
(53.3 - 50.9) = 2.4
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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