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3 years ago

10

If John has 69 apples and eats 66 apples how many does he have left?

1 answer:

stiks02 [169]3 years ago

3 0

Unless this is a trick question im saying 3

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Can someone please guide me step by step to sum the answer of the equation 5x(6)-10 ?

Leno4ka [110]

Answer:

30x-10

Step by Step Work:

5x(6)-10

Because 5 x 6= 30, it becomes

30x-10

Since 30x and 10 have different terms, you can not simplify any further.

So you get your answer, which is 30x-10.

3 0

2 years ago

Read 2 more answers

Find the 95% confidence interval for estimating the population mean μ

AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

$\displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}$

We are given these variables:

$\overline{x}=50$
$n=60$
$\sigma=10$

Plug these values into the formula for the confidence interval:

$\displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}$

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

$\displaystyle \frac{1-C}{2}=A$

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

$\displaystyle \frac{1-.95}{2}=.025$

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

$t^*=1.96$

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

$\displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}$

We can calculate the confidence interval, using this formula, to be:

$\boxed{(47.4697, \ 52.5303)}$

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0

1 year ago

Can someone help meeee pleaseeee!!!

inna [77]

I took the test it’s 29

4 0

3 years ago

Shannon walks 2,500 metres in 1 hour 40 minutes. <br> How far does she walk in one minute?

stich3 [128]

Answer:

25m

Step-by-step explanation:

Shannon's rate is 2,500m/100min. Simplifying, we see that this is equal to 25m/1min.

So, she walks 25 m in one minute.

4 0

2 years ago

An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand

stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis $H_{0} =$ µ =800

alternative hypothesis $H_{1} =$ µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t = $\frac{x-μ}{\frac{sig}{\sqrt{n} } }$

$t = \frac{788-800}{\frac{45}{\sqrt{30} } }$

t = $\frac{12}{8.215}$ = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

7 0

3 years ago