y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Answer:
1/8
Step-by-step explanation:
To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.
There are three -pound bags.
There are six -pound bags.
There are four -pound bags.
Multiply the weight and number of each bag to find the total weight of each different weight bag.
Now, add the three totals.
Finally, subtract the total weight from four pounds in order to find which weight Carla needs.
So, Carla should pick one -pound bag of candy to total four pounds.
Answer:
2z-6
Step-by-step explanation:
2(z-3)
2(z)-2(3)=2z-6
