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3 years ago

Find the missing length.

Mathematics

1 answer:

Cloud [144]3 years ago

7 0

I’m guessing they are the same shaped, just enlarged. So all you gotta do if so is 18/10 which gives you 1.8 and then 7 x 1.8, this will give you 12.6
So the answer is 12.6, sorry if I’m wrong

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If there are 30 kids in a class and eleven of them were girls , what is the probability that a student picked a random girl ?

Tamiku [17]

Answer: 11/30

Step-by-step explanation:

11 girls out of 30 kids. 11/30 cannot be simplified.

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3 years ago

A study1 conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and th

dusya [7]

Answer:

a) Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

b) $z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

c) $z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

d) For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

Step-by-step explanation:

Information given

$X_{1}=688$ represent the number of men with smartphone

$X_{2}=671$ represent the number of women with smartphone

$n_{1}=989$ sample of men selected

$n_{2}=1012$ sample of women selected

$p_{1}=\frac{688}{989}=0.696$ represent the proportion of men with smartphone

$p_{2}=\frac{671}{1012}=0.663$ represent the proportion of women with smartphone

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value

Part a

We want to test if we have difference in the proportion owning a smartphone between men and women, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

Part b

The statistic for this case is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

Part c

Replacing the info given we got:

$z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

Part d

For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

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kotykmax [81]

Answer:

Step-by-step explanation:

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Kate jogged a total distance of 8 1/2 miles during the months of January and February if katie only jogged 1/4 mile everyday whi

swat32

Since in this equation we are dividing 17/2 by 1/4, we can think of this as multiplying 17/2 with 4/1 (or 4).

17 4
---- X ----- = 34
2 1

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Ostrovityanka [42]

Answer:

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in case you dont know A z-score tells you if the distribution it comes from is normal.

Step-by-step explanation:

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