Determine whether the given function is even,odd,or neither f(x)=2x^2+x^4

Caleb bought 3 bagels and 2 muffins for $7.00.

kolezko [41]

Answer:

Bagels= 1$ and Muffins= 2$

Step-by-step explanation:

if Caleb bought 3 bagels for 1$ each that is 3$ and 2 muffins for 2$ each is 4$ and 4+3=7$

if Jonathan bought 2 bagels for 1$ each that is 2$ and 5 muffins for 2$ each is 10$ and 10+2=12$

7 0

2 years ago

A circular garden has a circumference of 113 yards. Lars is digging a straight line along a diameter of the garden at a rate of

White raven [17]

Answer:

3

Step-by-step explanation:

Circumference = $2\pi r = \pi d$ , where r is radius, and d is diameter

d=113/3.14=35.987, which is approximately 36

At 12 yards per hour, it will take 36/12=3 hours

4 0

3 years ago

Z > 34. Which of the following statements is the best way to describe the value of z?

Arisa [49]

Answer:

B

Step-by-step explanation:

The open end is always going to be by the larger number.

4 0

3 years ago

Read 2 more answers

What are the prime numbers up until 100

Setler [38]

2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97

5 0

3 years ago

It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an

Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that $n = 200, \pi = \frac{122}{200} = 0.61$ .

We want to build an 80% CI, so $\alpha = 0.20$ , z is the value of Z that has a pvalue of $1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667$

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0

3 years ago