256 · 0.16 x 256 · 0.09=
40.96 x 23.04 = 943.7
Explained: The 256's in parentheses mean they are multiplied. So, this means that 256 x 0.16 = 40.96, and 256 x 0.09 = 23.04. Once you have both of those numbers, you multiply them both, then end up with 943.7.
I'm almost certain this is correct, but be sure to tell me if it's wrong!
Please find the attached photograph for your answer
The complete question is
find the slope of the tangent line and the equation of the tangent line at the given point, ![x^2y-5xy^2](https://tex.z-dn.net/?f=x%5E2y-5xy%5E2)
at the point (3,1).
Answer:
Tangent = 1/23 , equation of tangent = 23y - x = 20
Step-by-step explanation:
We are given the equation
![x^2y-5xy^2](https://tex.z-dn.net/?f=x%5E2y-5xy%5E2)
![+6=0](https://tex.z-dn.net/?f=%2B6%3D0)
upon differentiation the given function we get
d (![x^2y-5xy^2](https://tex.z-dn.net/?f=x%5E2y-5xy%5E2)
) /dt
= ![2xy +x^2dy/dx - 5y^2 -10xy dy/dx =0](https://tex.z-dn.net/?f=2xy%20%2Bx%5E2dy%2Fdx%20%20-%205y%5E2%20-10xy%20dy%2Fdx%20%3D0)
upon substituting x=3 ,y=1 we will get
dy/dx = 1/23
now the equation of the tangent will be
y-1 = 1/23 (x-3)
23 (y-1) = x- 3
23y - 23 = x -3
23y - x = 20
Answer:
Slope = -13/10
Step-by-step explanation:
In order to find a slope of an equation, you must use the equation for a slope:
Slope = (y2 - y1) / (x2 - x1)
Use the provided coordinates in order to plug in the x and y values:
(-19, 12)
(-9, 1)
y2 = 12
y1 = 1
x2 = -19
x1 = -9
( 12 - 1) / (-19 - -9) = (13) / (-19 + 9) = 13 / -10 = -13/10