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3 years ago

14

Explain the amendment process in your own words. Or, you can use the following chart to fill in details about the amendment proc

ess

1 answer:

crimeas [40]3 years ago

8 0

Answer:

i can answer if you tell me which amendment????

Step-by-step explanation:

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How is repeating decimals used in the real world? Plz help I don't know it

guapka [62]

Just say in the store hahaha bfebfefbevfwvtvt2vt2vt3v3t3bt3btt3tbt2b

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3 years ago

3/4x + 6 = 15 what is x

Maslowich

<span>(3/4)*x-6 = 15 // - 15

(3/4)*x-15-6 = 0

3/4*x-21 = 0 // + 21

3/4*x = 21 // : 3/4

x = 21/3/4

x = 28</span>

5 0

3 years ago

Read 2 more answers

A large high school offers AP Statistics and AP Calculus Among the seniors in this school 65% take AP Statistics, 45% take AP Ca

Igoryamba

Answer:

0.8

Step-by-step explanation:

P(AP statistics) = 65%

P(AP Calculus) = 45%

P(AP statistics n AP Calculus) = 30%

Probability of AP statistics or AP Calculus but not both :

Probability of event A or B :

P(AUB) = p(A) + p(B) - p(AnB)

P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)

= 0.65 + 0.45 - 0.30

= 0.8

= 80%

4 0

2 years ago

Hay dos veces la cantidad de manzanas que naranjas en un puesto de frutas. Después de que se vendieron 15 naranjas, hay tres vec

Nastasia [14]

Answer:

45

Step-by-step explanation:

4 0

3 years ago

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

$\dfrac{A}{A'}=\dfrac{P^2}{P'^2}$

We are given:

A=72 dm^2 , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. $\dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}$

on taking square root on both the side we get:

$\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'$

Now putting the value of P in equation (1) we obtain:

$\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272$

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0

3 years ago