The quadriatic portion of a quadriatic equation is actually the term x^2. On the other hand, the constant in a quadriatic equation are a, b, c, or whatever letter except for x, which is a variable.
No, 22 should stay on its own side but x needs to be alone. so start on the 7+3x side and get 22 alone.
22=7+3x should start with subtracting seven instead of 22 then dividing by 3 and you will find the answer
Step-by-step explanation:
Here, in step format, is how to solve a system with three equations and three variables:
Pick any two pairs of equations from the system.
Eliminate the same variable from each pair using the Addition/Subtraction method.
Solve the system of the two new equations using the Addition/Subtraction method.
Answer:
B. 
Step-by-step explanation:
Given:
A spherical ball just fits inside a cylindrical can, 20 centimeters tall, with a diameter of 20 centimeters.
diameter of Sphere = 20 centimeters
hence radius = half of diameter = 
Hence we need to find the volume of sphere.
Volume of sphere = 
Here r is the radius of the circle.
Hence Volume of sphere =
Hence Option B is the correct answer.
There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
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Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
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Whichever method you pick, the answer is: 38
