Is this a multiple choice question? If so what are the options?
My guess is 21
That "9 minutes" doesn't affect the outcome!
How many pieces of candy are in the bag at the beginning? How many of those are "fruit tart chews?" Write a fraction involving these 2 counts. Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20. What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together. Please show your work.
F(x)=|x|
a parent function is the basic function before it has undergone transformations.
Answer:
1/4 of them were rotten
rotten ones = 1/4 × 12 = 3
ones that weren't rotten = 12 - 3 = 9
Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
