Answer:
The question lacks options, the options are:
parents?
A.100% red/white-feather chickens.
B.50% white-feather chickens and 50% red/white-feather chickens.
C.33% white-feather chickens, 33% red-feather chickens, and 33% red/white-feather chickens.
D.25% white-feather chickens, 25% red-feather chickens, and 50% red/white-feather chickens
The Correct answer is D
Explanation:
According to the question, the hybrid chicken has a mixture of red and white feather phenotypes expressed at the same time. This tells us that the red and white alleles are CODOMINANT in the chicken i.e. none is dominant or recessive over the other.
Let's assume that (R) allele is the red feather colour while (r) allele is for white feather colour. Therefore, the red/white feathered chicken will have a Rr genotype. In a cross between two red/white feathered chicken (Rr), the following offsprings will be produced RR, Rr, Rr and rr
RR- Homozygous red feather d chicken (1/4 × 100=25%)
Rr- Hybrid Red/White feathered chicken (2/4 × 100=50%)
rr- Homozygous white feathered chicken (1/4 × 100=25%)
Explanation:
You didn't attach a picture so i'll just explain how to find the number of stomatas/mm^2.
first you find the surface by multiplying the length by the width
0.1*0.1=0.01mm^2
now you count the numer of stomatas in the picture
in0.01mm^2 you have.........................x stomatas
in 1mm you have ...............................y stomatas
y=100x
Answer:
B. A bias could skew the information and make it
inaccurate.
Explanation:
Answer: A. Dimerization (1), DNA binding (4), cAMP binding (3
Explanation:
Should be prophase because chromatin coils up, becoming shorter and thicker, thick enough to become visible when stained.
