<span>h= (-16t^2 + 28t + 7) </span>
find the derivative to get time<span>
<span>
h' = (-32t + 28)
When the ball reaches its maximum height, its
vertical velocity (h’) will be 0 </span></span>
<span>
<span>
0 = -32t + 28 </span></span>
-32t=-28
<span><span>-28/-32 = </span>0.875
seconds </span><span>
<span>
The ball reaches its maximum height in 0.875
seconds after being thrown; plug and chug and:
h= (-16(0.875)^2 + 28(0.875) + 7) = 19.25 feet</span></span>
Max height = 19.25 feet, time = 0.88 seconds
Answer:
3142
Step-by-step explanation:
1727 + 1415 = 3142
Hello,
y=x²-7x+18
y''=2>0 ==> opens up.
Answer C
The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
Read more about translation at:
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Answer:
7
Step-by-step explanation:
took teh test
