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2 years ago

9

Drag the correct graph of each equation into the apace next to that equation to show how the output y-values change with changes

in the output

1 answer:

Vinvika [58]2 years ago

6 0

Answer:

I can't see the exercise. what do you want?

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The cost of a layer cake is $17 plus $5 per layer. If Paul has only $30 to spend on a cake, what is the most number of layers he

VikaD [51]

Answer:

The most number of layers he can afford is 2

Step-by-step explanation:

We automatically have a fee of 17 so we know we have 13 dollars remaining. Using this information, we know that one layer is 5 dollars which means we can get 2 layers which is equal to 10 dollars which turns our total fee to $27. Hope this helps!

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3 years ago

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For what value of B is the trigonometric function considered an odd function? y=cosB(x-c)

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For what value of B is the trigonometric function considered an odd function? y=cosB(x-c)

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3 years ago

Evaluate this expression for b= 3, and a=2. b-a

almond37 [142]

Substitute the values in the expression
b-a=3-2=1
answer b-a=1

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3 years ago

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I will mark that person brainliest if they answer correctly and must be well explained

Zolol [24]

it is 180

hope this helps

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3 years ago

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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

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2 years ago