The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
answer is 57.
Step-by-step explanation:
Given
m<6= x - 8
m<7 = 2x - 7
We know
<6 + <7 = 180° [ being linear pair ]
x - 8 + 2x - 7 = 180°
3x - 15 = 180°
3x = 180° + 15°
3x = 195°
x = 195° / 3
x = 65°
Now
m<6= x - 8 = 65° - 8° = 57°
hope it helps :)
Answer:
B. Stratified random sample is the correct answer
Answer:
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Step-by-step explanation: