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allochka39001 [22]
3 years ago
8

What is deviation from mean

Mathematics
2 answers:
Blababa [14]3 years ago
6 0
The word main is action of departing from an established course.
Vika [28.1K]3 years ago
3 0
For math- The difference between a value of a variable and another variable which usually ends up to be the variables mean
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107,600 115,220 104,910 median, mode, mean
san4es73 [151]

Answer:

<u>1. Mean =  342.7 (Rounding to the nearest tenth)</u>

<u>2. Median =  167.5 </u>

<u>3. Mode = There isn't a mode for this set of numbers because there isn't a data value that occur more than once. </u>

Step-by-step explanation:

Given this set of numbers: 107, 600,  115, 220,  104, 910, find out these measures of central tendency:

1. Mean = 107 + 600  + 115 + 220 + 104 + 910/6 = <u>342.7</u> (Rounding to the nearest tenth)

2. Median. In this case, we calculate it as the average between the third and the fourth element, this way:

115 + 220 =335

335/2 = <u>167.5 </u>

3. Mode = <u>There isn't a mode for this set of numbers because there isn't a data value that occur more than once. All the data values occur only once.</u>

5 0
3 years ago
The right cylinder in the diagram has a volume of 450 cm3. The other cylinder has a slant length of 10 cm, but the same base are
mezya [45]
A tilted or slanted cylinder has the same volume as its equivalent right cylinder, provided that
(a) the two bases of the tilted cylinder are parallel,
(b)  the base areas of the tilted and right cylinders are equal,
(c) the vertical height of the right and tilted cylinders are equal.

This fact can be verified by slicing the tilted cylinder into thin, flat washers, as in integral calculus.

Because all 3 conditions are satisfied, the volume of the tilted cylinder is 450 cm³.

Answer: 430 cm³
5 0
3 years ago
: A new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.
d1i1m1o1n [39]

Answer:

2 bears in 2020.

Step-by-step explanation:

We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

We will use exponential decay formula to solve our given problem as:

y=a\cdot (1-r)^x, where,

y = Final quantity,

a = Initial value,

r = Decay rate in decimal form,

x = Time

20\%=\frac{20}{100}=0.20    

Upon substituting our given values in above formula, we will get:

y=150(1-0.20)^x

y=150(0.80)^x, where x corresponds to year 2000.

To find the population in 2020, we will substitute x=20 in our equation as:

y=150(0.80)^{20}

y=150(0.011529215046)

y=1.7293822569    

y\approx 2

Therefore, 2 bears are there predicted to be in 2020.

Since population is decreasing so population is best described as exponential decay.

8 0
3 years ago
4x minus 9(3 minus x)
ANEK [815]

Answer:

13x-27

Step-by-step explanation:

Simplify the expression.

7 0
3 years ago
There are 20 goldfish in a pond. Their population is increasing by 20% each year. The same pond has 100 minnows. The minnow popu
Kay [80]
The graph is attached, showing the intersection point at 13.5 years and populations of 235.2 for each population.

We only consider the portion of the graph from x=0 on, since negative time is illogical.  Tracing the graph we get the intersection point.

3 0
3 years ago
Read 2 more answers
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