What do I have to do in this math problem

PLEASE HELP FOR BRAINLIEST if UW bisects

Semenov [28]

Answer:

If it does bisect it would be Tuv

Step-by-step explanation:

It would join it together

8 0

3 years ago

Read 2 more answers

The increase in the number of humans living on Earth (N, as measured in billions) with time t (as measured in years since 1800)

NemiM [27]

Answer:

The slope of the line would be 0.00910 in a logarithm graphic.

Step-by-step explanation:

Statement is incomplete. The correct sentences are: The increase in the number of humans living on Earth (N, as measured in billions) with time t (as measured in years since 1800) is modeld by the following function: N = 0.892e^0.00910t. If you were to graph in ln (N) versus t, what would be the slope of the line?

Let be $N(t) = 0.892\cdot e^{0.00910\cdot t}$ , where $N(t)$ is the number of humans living on Earth, measured in billions, and $t$ is the time, measured in years since 1800. As we notice, this is an exponential function and its slope is not constant and such expression have to be linearized by using a logartihm graphic. We add logarithms on each side of the formula and simplify the resulting expression by means of logarithmic properties:

$\log N(t) = \log \left(0.892\cdot e^{0.00910\cdot t}\right)$

$\log N(t) = \log 0.892 + 0.00910\cdot t$

In a nutshell, the slope of the line would be 0.00910 in a logarithm graphic.

4 0

3 years ago

-3/4x+5/6y=15 x-intercept= y-intercept=

Trava [24]

To make this easier, you need to change the fractions by multiplication.

-3/4x=15 - First, you multiply 4 to both sides of the equation

(4)-3/4x=15(4)

-12/4x=60 - Simplify

-3x=60 - Divide by -3 on both sides

x=-20 -> (-20,0)

Do the same to find the y-intercept, to get (0,18)

5 0

4 years ago

Write 2/25 as a percent

ladessa [460]

The answer to this is 8%.

8 0

3 years ago

For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____.a. exactly norm

maxonik [38]

Answer:

Approximately normal for large sample sizes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

The distribution is unknown, so the sampling distribution will only be approximately normal when n is at least 30.

So the correct answer should be:

Approximately normal for large sample sizes

7 0

4 years ago