Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
Answer:
173x^2+107x+24
Step-by-step explanation:
9x-x^2+7x+8+10x-x^2+19x+8-x^2+26x+88x^2+10x+88x^2+26x+8
173x^2+107x+24
22-7-7-7=1 this will show that you can subtract 7 three times from 22 and have a remainder of 1.
Answer:
61 is the length of AD. Hope this helps!
(-oo, 42)
Mark brainliest
Hope this helps you
Graph that then it won’t let me send pic
