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Yuliya22 [10]
3 years ago
9

Hey:) can you please help me posted picture of question

Mathematics
2 answers:
kupik [55]3 years ago
7 0
Option A gives the correct answer.

Step by step solution is listed below:

( x^{2} +x+8)(x-5) \\  \\ 
=x( x^{2} +x+8)-5( x^{2} +x+8) \\  \\ 
= x^{3}+ x^{2} +8x-5 x^{2} -5x-40 \\  \\ 
= x^{3}-4 x^{2} +3x-40
tatiyna3 years ago
6 0
We have the following expression:
 (x2 + x + 8) (x - 5)
 Rewriting we have:
 x3 + x2 + 8x + (-5x2 - 5x - 40)
 Adding similar terms:
 x3 - 4x2 + 3x - 40
 Answer:
 
The solution for this case is given by:
 
x3 - 4x2 + 3x - 40
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O points
astraxan [27]

7.5 %

Step-by-step explanation:

We by finding how far from the mean the 999 volume caps are, using z score;

Z = (x – μ) / σ

Z = (999 – 998) / 7

Z = 0.143    

We use the z-table to find the confidence levels;

= 85%

= 0.85

Since we are finding proportion of bottles have volumes greater than 999

mL;

1 – .85 = .15

0.15/2 = 0.075

= 7.5%

5 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST
Elis [28]

Answer:

5

Step-by-step explanation:

<u>move constant</u>

x+7 ≥ 12

<u>subtract</u>

x≥ 12-7

<u>solution</u>

x ≥ 5

4 0
2 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
Explain why all squares are similar????? and please help with question below!!!!!!!!!!!!!
Oliga [24]
That's not a squre
anyway, we use ratios
base:person to corner=28:8
height to height=x:5
so
28/8=x/5 becasue same ratio
28/8=14/4=7/2
7/2=x/5
multiply
35/10=2x/10
35=2x
divide 2
17.5=x

x=17.5 feet
5 0
3 years ago
Can someone help me with question please :) .
navik [9.2K]

Answer: C,D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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