Answer:9
Step-by-step explanation:
Find the prime factorization of 72
72 = 2 × 2 × 2 × 3 × 3
Find the prime factorization of 135
135 = 3 × 3 × 3 × 5
To find the GCF, multiply all the prime factors common to both numbers:
Therefore, GCF = 3 × 3
GCF = 9
Step-by-step explanation:
0 10
0-6
this is the answer. I am sure
The race is 3 miles.
21 minutes divided by 7mph (miles per hour)= 3 miles
From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
More can be learned about confidence intervals at brainly.com/question/25890103
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<h3>16 lollipops and 9 bags of chips are sold</h3>
<em><u>Solution:</u></em>
Let "x" be the number of lollipops sold
Let "y" be the number of bags of chips sold
Cost of 1 lollipop = $ 1.50
Cost of 1 bag of chip = $ 1.75
<em><u>Yesterday Lucy made $39.75 from selling a total of 25 lollipops and bags of chips</u></em>
Therefore,
x + y = 25
y = 25 - x -------- eqn 1
<em><u>Yesterday Lucy made $39.75</u></em>
Therefore,
number of lollipops sold x Cost of 1 lollipop + number of bags of chips sold x Cost of 1 bag of chip = 39.75
1.5x + 1.75y = 39.75 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
1.5x + 1.75(25 - x) = 39.75
1.5x + 43.75 - 1.75x = 39.75
0.25x = 4
<h3>x = 16</h3>
<em><u>Substitute x = 16 in eqn 1</u></em>
y = 25 - 16
<h3>y = 9</h3>
Thus 16 lollipops and 9 bags of chips are sold