Question

Given that in isosceles △ABC , base BC¯¯¯¯¯, BE¯¯¯¯¯⊥AC¯¯¯¯¯, and CF¯¯¯¯¯⊥AB¯¯¯¯¯, which of the following proves that BE¯¯¯¯¯≅CF¯¯¯¯¯?
1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. ∠BEA and ∠CFA are Supplementary Angles (Def. of ⊥)
5. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Supp. ∠s ≅ Thm.)
6. ∠A≅∠A (Reflex. Prop. of≅)
7. △ABE≅△ACF (SAS Steps 1, 6, 5)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. ∠BEC and ∠CFB are Supplementary Angles (Def. of ⊥)
5. AC¯¯¯¯¯≅BC¯¯¯¯¯ (Supp. ∠s ≅ Thm.)
6. ∠A≅∠B (Sym. Prop. of≅)
7. △ABE≅△ACF (SAS Steps 1, 6, 5)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅AC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. m∠BEA=m∠CFA=90∘ (Def. of ⊥)
5. ∠BEA≅∠CFA (Rt. ∠s ≅ Thm.)
6. ∠A≅∠A (Reflex. Prop. of≅)
7. △ABE≅△ACF (AAS Steps 5, 6, 1)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅AC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. m∠BEC=m∠CFB=90∘ (Def. of ⊥)
5. ∠BEC≅∠CFB (Rt. ∠s ≅ Thm.)
6. ∠A≅∠B (Sym. Prop. of≅)
7. △ABE≅△ACF (AAS Steps 5, 6, 1)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

Answer 1

Answer:

cf--__ lab _Ab is the answer total

Step-by-step explanation:

simple