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babunello [35]
2 years ago
15

My I pless have a little help play just with one little thing (3^2 * 3^3)2

Mathematics
2 answers:
Ymorist [56]2 years ago
8 0

(3^2 \cdot 3^3)^2 \\\\= (3^{2+3})^2\\\\= (3^5)^2\\\\ =3^{5\cdot 2} \\\\=3^{10}

Bad White [126]2 years ago
5 0

( { {3}^{2} \times  {3}^{3}  })^{2}

▪▪▪▪▪▪▪▪▪▪▪▪▪

<h3>Solution:-</h3>

= ( { {3}^{2} \times  {3}^{3}  })^{2}

{ {a}^{m}  \times  {a}^{n} } =  {a}^{m + n}

=  ({ {3}^{2 + 3} })^{2}

=  ({3}^{5})^{2}

=  {3}^{5 \times 2}

=  {3}^{10}

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If it takes you 40 minutes to go 20 miles downstream and then 60 minutes on the way back, what is the speed of the current?
IrinaK [193]

Answer:

Speed of Current = 5 miles per hour

Step-by-step explanation:

We know distance formula,

D = RT

Where

D is distance

R is rate

T is time

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Upstream rate is (against current) = x - c

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D = RT

20 = (x + c)(40)

and

60 minutes to go upstream, 20 miles, that means:

D = RT

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Simplifying first equation:

40x + 40c = 20

Simplifying second equation:

60x - 60c = 20

Multiplying first equation by 60, we get:

60 * [40x + 40c = 20] = 2400x + 2400c = 1200

Multiplying second equation by 40, we get:

40 * [60x - 60c = 20] = 2400x - 2400c = 800

Now we add up both these equations:

2400x + 2400c = 1200

2400x - 2400c = 800

----------------------------------

4800x = 2000

x = 2000/4800 = 5/12

We need speed of current, that is "c", so we plug in the value of x into first equation and solve for c:

40x + 40c = 20\\40(\frac{5}{12}) + 40c = 20\\\frac{50}{3}+40c=20\\40c=20-\frac{50}{3}\\40c=\frac{10}{3}\\c=\frac{1}{12}

Speed of Current = 1/12 miles per minute

Since there is 60 minutes in an hours, that would be:

(1/12) * 60 = 5 miles per hour

Speed of Current = 5 miles per hour

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