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2 years ago

Find the Perimeter of the figure below, composed of a rectangle and two semicircles. Round to the nearest tenths place.

Mathematics

1 answer:

NISA [10]2 years ago

5 0

281.25 is the answer i think

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Find x and y, given that KL and line MN are parallel. Show all work

Setler [38]

$\dfrac{|MN|}{|NJ|}=\dfrac{|KL|}{|LJ|}\\\\\dfrac{22}{12+8}=\dfrac{y}{8}\\\\\dfrac{22}{20}=\dfrac{y}{8}\ \ \ |cross\ multiply\\\\20y=22\cdot8\\\\20y=176\ \ \ |:20\\\\\boxed{y=8.8}$

$\dfrac{|MK|}{|KJ|}=\dfrac{|NL|}{|LJ|}\\\\\dfrac{x-2}{5}=\dfrac{12}{8}\ \ \ \ |cross\ multiply\\\\8(x-2)=5\cdot12\\\\8x-16=60\ \ \ |+16\\\\8x=76\ \ \ |:8\\\\\boxed{x=9.5}$

4 0

2 years ago

Read 2 more answers

What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)

UkoKoshka [18]

Answer:

$\boxed{m = - \frac{33}{14} }$

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

$m$ is a slope
$(x_1,~y_1)$ and $(x_2,~y_2)$ are the point of the line

So, the slope is

$(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1$

$(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}$

$m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }$

$m = \frac{\frac{11}{2} }{\frac{-7}{3} }$

$m = \frac{11}{2} \div (-\frac{7}{3} )$

$m = \frac{11}{2} \times (-\frac{3}{7} )$

$m = - \frac{33}{14}$

Happy to help:)

7 0

3 years ago

Read 2 more answers

Help please and thank you

lara [203]

Cannot be determined.
Area or perimeter should be provided to calculate the lenght but its not.

8 0

2 years ago

HOW DO I SOLVE THIS??<br> What would the answer be??<br> THANKS!

Arisa [49]

Convert 300% into decimals. So move the decimal point 2 times to the left and you get 3.00 and multiply it by 5 and square it because area of square is s^2

7 0

3 years ago

Seventh grade

kupik [55]

-5+1+-2+9v+-5v

-3+1+4v

-2+4v

5 0

2 years ago