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Oliga [24]
3 years ago
15

Rewrite the subtraction number sentence as an addition number sentence.5- (-2)​

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

5 + 2          

Step-by-step explanation:

We have to rewrite the given statement in addition form.

The integers have  property of:

Negative(-)  Negative(-) = Positive(+)

Positive(+)  Positive(+)  = Positive(+)

Positive(+)  Negative(-) = Negative(-)

Negative(-) Positive(+)  = Negative(-)

The given statement is:

5-(-2)

Since we have two negative together, it is converted into a positive.

Thus, the given statement can be written in positive form as

5 + 2

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Find the coordinates of the midpoint of the segment whose endpoints are H(5, 13) and K(7, 5). (12, 18) (9, 7) (2, 8) (6, 9)
____ [38]

Answer: D. (6, 9)

<u>Step-by-step explanation:</u>

Midpoint is the "average" of the x's and y's:

Given: (5, 13) and (7, 5)

Midpoint: (\dfrac{5+7}{2},\dfrac{13+5}{2})

             = (\dfrac{12}{2},\dfrac{18}{2})

              = (6, 9)

4 0
3 years ago
Dilate the trapezoid using center (-3,4) and scale factor 1/2.
pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2)  (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2)  (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2)  [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k  [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0
1 year ago
Solve using substitution method. 3×-4y=18 and 2x + y = 1
Shalnov [3]
3x - 4y = 18 ⇒ 3x -  4y = 18
2x +  y =   1 ⇒ 8x + 4y =   4
                              11x = 22
                               11     11
                                  x = 2
                          2x + y = 1
                       2(2) + y = 1
                           4 + y = 1
                         - 4        - 4
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3 0
3 years ago
Which of the lines graphed has a slope of -1/2 and a y-intercept of 3?
VARVARA [1.3K]

Answer:

The answer is image 3.

Step-by-step explanation:

The equation for the line will be y = (-1/2)x + 3 so the gradient is negative and you will have to find the x-intercept and y-intercept.

x-intercept :

let \: y = 0

0 =   - \frac{1}{2} x + 3

\frac{1}{2} x = 3

x = 3 \div  \frac{1}{2}

x = 6

y-intercept :

let \: x = 0

y =  -  \frac{1}{2} (0) + 3

y = 3

8 0
3 years ago
Read 2 more answers
8a - 2b + 12a - 2a - 4b
chubhunter [2.5K]

-52

Step-by-step explanation:

8.4-2.22+12.4-4.22=

=32-44+48-88=

=-132+80=

=-52

8 0
3 years ago
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