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ozzi
3 years ago
6

20 POINTS !!!!!!!!!

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

x =  x = 9 ±\sqrt{13}  or x ≈ 12.61 or  x ≈ 5.39

Step-by-step explanation:

x² - 18x + 68            Solve by completing the square.

x² - 18x = - 68    

Now complete the square and add that number to both sides of the equation.

1/2 (of the coefficient of the x term)² = (1/2 · -18)² = 81 .

x² - 18x + 81  = -68 + 81

(x - 9) (x - 9) = 13                  Now find the square root of both sides

\sqrt{(x - 9)(x - 9)} =\sqrt{13}            Solve

x - 9 = ±\sqrt{13}                         Solve for x

x = 9 ±\sqrt{13}  

x = 9 + \sqrt{13}    or  x = 9 - \sqrt{13}      

x ≈ 12.61      or x ≈ x  5.39            

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Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in
lyudmila [28]

Answer:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

7 0
3 years ago
Can someone help me find the slope
Serggg [28]

Answer:

I believe the answer is C,  -4/5.

Step-by-step explanation:

You first find two points on the line and substitute them into the slope formula. I used points (-10,10) and (5,-2).  

1. y_2-y_1/x_2 - x_1

2. -2-10/5-(-10)

3. -12/15

4. -4/5

I hope this helps, sorry for the late response.

6 0
3 years ago
Which of these sets of angle measures could be the three angles in a triangle?
vazorg [7]
50, 60 , 70 can be three angles in a triangle
3 0
3 years ago
Read 2 more answers
Each cable car at an amusement park can hold six Riders. There are 51 people in line to ride the cable cars. How many cable cars
laila [671]

Answer:

9 cable cars

Step-by-step explanation:

51 ÷ 6 = 8.5

8.5 rounds up to 9

Answer:

3

Step by step explanation:

54 ÷ 6 = 9

5 0
3 years ago
The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is f(x)=0.0
faltersainse [42]

Answer:

a) 0.2

b) 0.4

c) Mean  = 62.5

Variance = 52.083              

Step-by-step explanation:

We are given the following information in the question:

f(x) = 0.4\\

a = 50, b = 75

We are given a uniform distribution.

a) P(x > 70)

P(x > 70)\\=1 - P( \leq 70)\\\\=1-\displaystyle\int^{70}_{50}0.04 ~dx\\\\=1-0.04(70-50)\\=0.2

b) P(x < 60)

P(x < 60)\\\\=\displaystyle\int^{60}_{50}0.04 ~dx\\\\=0.04(60-50)\\=0.4

c) Mean:

\mu = \displaystyle\frac{a+b}{2}\\\\\mu = \frac{50+75}{2} = 62.5

Variance:

\sigma^2 = \displaystyle\frac{(b-a)^2}{12}\\\\= \displaystyle\frac{(75-50)^2}{12} = 52.083

4 0
3 years ago
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