Given: △ABC, m∠A=60°, m∠C=45°, AB=9 Find: Perimeter of △ABC, Area of △ABC

Mathematics

1 answer:

docker41 [41]3 years ago

6 0

i hope my handwriting isnt too bad and that this helps!

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Solve for m

MakcuM [25]

Answer:

m = 29/48

Step-by-step explanation:

Given that

x₂ = (y₂-y₁) +10 →(1

y₂ = y₁-x₁ → (2

y₁= 37

x₁ = 29

Now substitute the value of x₁ and y₁ into equation 2

y₂ = 37-29

y₂ = 8

Now substitute the value of y₂ and y₁ into equation 1

x₂ = (8-37) +10

x₂ = -19

As we know the slope (m) can be calculated as follows

m =(y₂ - y₁)/(x₂ - x₁)

m = (8- 37)/(-19 - 29)

m = (-29)/(-48)

m = 29/48

So our slope is 29/48

3 0

3 years ago

Which system of equations is represented by the matrix below? 1 5 11 4 -6-3 A. y + 5x = 11 4y - 6x = -3 B. X+ 5y = 11 4x - 6y =

Vitek1552 [10]

Answer: Choice B

$x+5y = 11\\4x-6y = -3$

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Explanation:

The given matrix is

$\left[\begin{array}{cc|c}1&5&11\\4&-6&-3\end{array}\right]$

The numbers to the right of the vertical bar represent the values on the right hand side of each equation in the final answer.

The numbers to the left of the bar represent the x and y coefficients of the equations. The first number of any given row is the x coefficient. The second number is the y coefficient.

For instance, the first row has $\begin{array}{cc}1&5\end{array}$ to indicate the x coefficient is 1, and the y coefficient is 5. We end up with 1x+5y or simply x+5y. Putting everything together, the first equation would be x+5y = 11