Answer:
B. 2, -0.5
Step-by-step explanation:
Given the equation
Rewrite it as
Graph the graph of the quadratic function
The grapg of this function is a parabola going downwards.
This parabola intersects the x-axis at points x = -0.5 and x = 2, so the solutions of the equation are x = -0.5 and x = 2
<u>ANSWER: </u>
If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second
<u>SOLUTION: </u>
Given, a ball is thrown into the air with a velocity of 34 feet per second
Initial velocity (u) = 34 feet per second
And also given a relation between displacement and time = --- eqn 1
We need to find the velocity when t = 1 ; v = ?
We know that, v = u + at and
where v is instantaneous velocity and u is initial velocity
a is acceleration
t is time interval
s is displacement
using the displacement and time relation eqn (1) we get
Now, when t = 1, displacement s = 34(1) – 16(1)
here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s
now put a value in v = u + at
v = 34 + (-32)(1)
v = 34 – 32
v = 2 ft/s
Hence, velocity of the ball after 1 second is 2 ft/s