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laila [671]
2 years ago
6

Can somone pls c h a t me

Mathematics
2 answers:
zloy xaker [14]2 years ago
5 0
Hey bestie. I really don’t know what to say except for Pinterest is probably the place for you. There’s a bunch of people looking for friends there. Best of luck.
r-ruslan [8.4K]2 years ago
4 0

Answer:

no

Step-by-step explanation:

go seek some therapy

+1 972-423-3555

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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
What is the perimeter of the framed picture in terms of x? ( x + ) inches
Marysya12 [62]

Answer:

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Step-by-step explanation:

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3 years ago
9. I NEED HELP ASAP!! PLEASE PUT AND ANSWER AND STEP BY STEP EQUATION!! IF YOU DON'T KNOW THE ANSWER DON'T PUT ANYTHING!!
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9.) Answer: B. f(x) = 4 - x



Explanation/Proof:

If we substitute, the answers are correct.

f(x) = 4 - (1)

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f(x) = 4 - (2)

f(x) = 2 ✅


And so on and so forth.

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18 divided by 3 is 6
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