Answer:
The cross-section of the rectangular prism is a:
Step-by-step explanation:
When you take a cross-section of a rectangular prism, regularly <u>you will obtain a rectangle because this was the base or the two-dimension figure that was used to form the three-dimension figure, in this case, the rectangular prism</u>, the form of obtaining other figure is using how reference the square face, in that case, the cross-section would be a square, this happens because the cross-section is bind with the reference face. Possibly you think the cross-section in the figure doesn´t appear a rectangle, <u>this happens by the perspective because we are looking at the rectangular prism with an inclination of 45°, but if the inclination was 90°, you would see a blue rectangle</u>.
Answer:
Yes it goes in a straight line
Step-by-step explanation:
Answer:
(20,-4)
Step-by-step explanation:
We are given;
One end point as (2,5)
Point of division as (10,1)
The ratio of division as 4:5
We are required to calculate the other endpoint.
Assuming the other endpoint is (x,y)
Using the ratio theorem
If the unknown endpoint is the last point on the line segment;
Then;
![\left[\begin{array}{ccc}10\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
=![\frac{4}{5} \left[\begin{array}{ccc}x\\y\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D)
+![\frac{5}{9}\left[\begin{array}{ccc}2\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
Therefore; solving the equation;
solving for x
x = 20
Also
solving for y
y= -4
Therefore,
the coordinates of the end point are (20,-4)
