<span>The number of ancestors going back through the <em>5th generation</em>, including Tle-nle and counting <em>Tle-nle as the 1st generation</em> is:
= 1 + 3 + 3^2 + 3^3 + 3^4
= (3^5 - 1) / (3 - 1)
= 242 / 2
= 121
Since we included </span>Tle-nle as the 1st generation, we will only compute up to the 4th power. If it is until the 6th generation, add 3^5 to the equation.
Answer:
6x²y²
Step-by-step explanation:
6: 1 2 3 6
18: 1 2 3 6 9 18
36: 1 2 3 4 6 9 12 18 36
the common factor for 6 18 and 36 are
1 2 3 6
x² = x × x
y³ = y × y × y
x³ = x × x × x
y³ = y × y × y
x³ = x × x × x
y² = y × y
the common factor are for x and y are
x² y²
Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²
The program is an illustration of loops
<h3>What are loops?</h3>
Loops are program statements that are used to perform repetition
<h3>The main program</h3>
The program written in Python, where comments are used to explain each line is as follows:
#This initializes sum to 0
summ = 0
#This gets input for the first number
num = int(input())
#This is repeated while num is not -1
while num!= -1:
#This calculates the sum
summ+=num
#This gets input for the num
num = int(input())
#This prints the sum
print(summ)
Read more about loops at:
brainly.com/question/16397886
Example Problems<span>Find the value of "x": 5x = 25. Step 1 : The product is 25 and the given divisor is 5 . Given 5x = 25 . Divide by 5 on both the sides. 5 x 5 = 25 5 . ...<span>Find the value of "x" : 7x = 56; Step 1 : The product is 56 and the given divisor is 7. Given 7x = 56 . Divide by 7 on both the sides. 7 x 7 = 56 7 .</span></span>
So it would equal to 8/10 and divide by 2 which you would get 4/5
