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3 years ago

7-12, in 7&8 trace line m and point m

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

5 0

Answer:

sorry i neeeeeeeeeeeeeed the points

Step-by-step explanation:

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-2/3x+7(3/7-3/7x) -12 divided by 6*3

Anna71 [15]

Answer:

x = (-27)/11

Step-by-step explanation:

Solve for x:

(-11 x)/54 - 1/2 = 0

Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:

(-27)/54 - (11 x)/54 = 0

(-27)/54 - (11 x)/54 = (-11 x - 27)/54:

(-11 x - 27)/54 = 0

Multiply both sides of (-11 x - 27)/54 = 0 by 54:

(54 (-11 x - 27))/54 = 54×0

(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:

-11 x - 27 = 54×0

0×54 = 0:

-11 x - 27 = 0

Add 27 to both sides:

(27 - 27) - 11 x = 27

27 - 27 = 0:

-11 x = 27

Divide both sides of -11 x = 27 by -11:

(-11 x)/(-11) = 27/(-11)

(-11)/(-11) = 1:

x = 27/(-11)

Multiply numerator and denominator of 27/(-11) by -1:

Answer:x = (-27)/11

5 0

3 years ago

How would i go about simplifying (x+h)^3?

Sindrei [870]

H^3+3h^2x+3hx^2+x^3 should be the answer

7 0

3 years ago

Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).

Ludmilka [50]

A line segment can be divided into ratios.

The coordinate of P on line segment AB is (5,1)

Given

$A = (-3,-5)$

$B = (9,4)$

The position of P from A to B is:

$P_A = \frac 23$

So, from P to B would be:

$P_B =1 - \frac 23$

$P_B = \frac 13$

So, the ratio is:

$m : n = \frac 23 : \frac 13$

Simplify

$m : n = 2 :1$

The coordinate of point P is:

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

So, we have:

$P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})$

$P = (\frac{15}{3},\frac{3}{3})$

$P = (5,1)$

Hence, the coordinate of P is (5,1)