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gizmo_the_mogwai [7]
3 years ago
13

Solve for a 7a + 2a + a − 9a = 20

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

a = 20

Step-by-step explanation:

7a + 2a + a − 9a = 20

Combine like terms

10a -9a = 20

a =20

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Since the shirt is 25 percent off your paying for 75 percent of the shirt. 0.75(36) is 27. The shirt will cost 27.00
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vovikov84 [41]

Answer:

Step-by-step explanation:

  x + 6 I x³ + 2x²  - 10x + 84   I   x² - 4x + 14

              x³ + 6x²

            <u> -     -       </u>

                     -4x² - 10x

                    -4x²  - 24x

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                               14x + 84

                                14x + 84

                               <u> -      -       </u>

                                     0

P(x)  =(x +6)* ( x² - 4x + 14) + 0

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2 years ago
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Answer:

Step-by-step explanation:

b)

5 0
2 years ago
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3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
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