we know that
cup of flour is used to make 
dinner rolls.
Part a) How much flour is needed to make one dinner roll?
by using proportion
therefore
the answer Part a) is
To make one dinner roll is needed 
cup of flour
Part b) How many cups of flour are needed to make 3 dozen dinner rolls?
Multiply the value obtained in part a) by 
so
therefore
the answer Part b) is
To make 
dozen dinner rolls are needed 
cup of flour
Part c) How many rolls can you make with 5 2/3 cups of flour?
by using proportion
therefore
the answer part c) is
rolls
The answer would be the 3rd one, 10 to the power of 16 (10^16).
This is because you multiply the 2 powers (2 and 8) to get 16. When there is one power within a set of parenthesis and one power on the outside the parenthesis. Since there is a 10 to the 0 power (10^0) you add this power to 16 since it is multiplying integers with exponents. Thus getting 10^16 as an answer.
I hope this helps!
Answer:
$30.38
Step-by-step explanation:
To find the sale price, find the percentage you pay after the discount. The discount is for 38%. So you pay 62%.
The selling price of the scarf will be 0.62(49) = 30.38
Answer:
Step-by-step explanation:
If you graph there would be two different regions. The first one would be
And the second one would be
.
If you rotate the first region around the "y" axis you get that
And if you rotate the second region around the "y" axis you get that
And the sum would be 2.51+4.188 = 6.698
If you revolve just the outer curve you get
If you rotate the first region around the x axis you get that
And if you rotate the second region around the x axis you get that
And the sum would be 1.5708+1.0472 = 2.618
Step-by-step explanation:
The equation of a circle can be the expanded form of
\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)
2
+(y−b)
2
=r
2
where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.
Here, the equation of the circle is,
\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}
⟹
⟹
⟹
⟹
x
2
+y
2
+10x−4y−20
x
2
+y
2
+10x−4y+25+4−49
x
2
+y
2
+10x−4y+25+4
x
2
+10x+25+y
2
−4y+4
(x+5)
2
+(y−2)
2
=
=
=
=
=
0
0
49
49
7
2
From this, we get two things:
\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}
1.
2.
Center of the circle is (−5, 2).
Radius of the circle is 7 units.
Hence the radius is 7 units.
