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Lynna [10]
4 years ago
9

How do you know that volume of a diamond is 15.1g

Chemistry
1 answer:
marshall27 [118]4 years ago
4 0

Answer:

Density = mass / volume,  

        therefore volume = mass / density. Note that 1 mL = 1 cubic centimeter.

Explanation:

Volume = 15.1g / 3.52g/mL = 4.3mL = 4.3 cubic centimeters.

then a  diamond has a density of 3.52 g/mL.

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If 20 grams of sulfur reacts with 30 grams of oxygen, predict the mass of sulfur trioxide produced. Why would you expect this
Scilla [17]
20/32=0.625 moles of sulfur
30/16 = 1.875 moles of oxygen
The formula requires 1 mole of sulfur for 3 moles of oxygen which means that their is no limiting reactant as that is the ratio found thus it will react to completion forming 50 grams of product or sulfur trioxide
4 0
3 years ago
How many molecules of F2 in 90g F2
Bogdan [553]
I dont know good luck!
7 0
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Rutherford bombarded gold foil with alpha (a) particles and found that a small percentage of the particles were deflected. Which
Alex73 [517]

Answer:

The presence of neutrons

Explanation:

Based on gold foil experiments, Rutherford proposed a atomic model known as Rutherford'd model or nuclear model or planetary model of the atom.

As per this model, most of the mass of the atom is concentrated in the center of the atom known as nucleus.

Electrons revolve around it same as planet revolve around sun.

Since, neutrons had not been discovered at the time of Rutherford'd model, therefore, as per the Rutherford'd model, nucleus is only made of protons.

Therefore, the correct option is option B

8 0
3 years ago
1. Why do scientists use a standard measurement system?
Margaret [11]

Answer:

Explanation:

1.Scientists use a shared system for reporting measurements called the International System of Units (SI). We use common measurement systems because science involves a lot of replication to confirm results. The most common system used in science is the metric system.

2.m, kg, m^3

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3 0
3 years ago
Read 2 more answers
A 0.200 M solution of a weak acid, HA, is 9.4% ionized. Using this information, calculate Ka for HA.
slavikrds [6]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Initial concentration of weak acid HA = 0.200 M

and dissociation constant ({ \alpha}) is :

\qquad \sf  \dashrightarrow \:  \alpha =  \frac{dissociation \:  \: percentage}{100}

\qquad \sf  \dashrightarrow \:  \alpha =  \frac{9.4}{100}  = 0.094

Now, at initial stage :

  • \textsf{ Conc of HA = 0.200 M}

  • \textsf{Conc of H+ = 0 M}

  • \textsf{Conc of A - = 0 M}

At equilibrium :

  • \textsf{Conc of HA = 0.200 - 0.094(0.200) = 0.200(1 - 0.094) = 0.200(0.906) = 0.1812 M}

  • \textsf{Conc of H+ = 0.094(0.200)  = 0.0188 M}

  • \textsf{Conc of A - = 0.094(0.200)  = 0.0188 M}

Now, we know :

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}}

( big brackets represents concentration )

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}}

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}}

\qquad \sf  \dashrightarrow \: { K_a \approx 0.00195 }

\qquad \sf  \dashrightarrow \:  {K_a \approx 1.9 × {10}^{-3} }

7 0
2 years ago
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