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4 years ago

How do you know that volume of a diamond is 15.1g

Chemistry

1 answer:

marshall27 [118]4 years ago

4 0

Answer:

Density = mass / volume,

therefore volume = mass / density. Note that 1 mL = 1 cubic centimeter.

Explanation:

Volume = 15.1g / 3.52g/mL = 4.3mL = 4.3 cubic centimeters.

then a diamond has a density of 3.52 g/mL.

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N2 + 3 H2 --> 2 NH3

Anna71 [15]

Answer:

4 moles of NH3 will be produced

Explanation:

The reaction expression is given as:

N₂ + 3H₂ → 2NH₃

We have to check that the equation of the reaction is balanced.

Then;

if 2 mole of N₂ reacts;

1 mole of N₂ will react with 3 mole of H₂ to produce 2 mole of NH₃

2 mole of N₂ will react with (2x3)mole of H₂ to produce (2x2)mole of NH₃

6mole of H₂ to produce 4 mole of NH₃

7 0

3 years ago

Sulfuric acid is formed when sulfur dioxide reacts with oxygen and water. Write a balanced chemical equation for the reaction. (

Nesterboy [21]

Balanced chemical equation for the reaction is:

2S $O_{2}$ (g) + $O_{2}$ (g)+ 2 $H_{2}$ O (l) ⇒ $H_{2} S_{} O_{4}$

Moles of $H_{2} S_{} O_{4}$ formed is 5.75 moles.

Moles of oxygen used is 5.75 moles in the reaction.

Explanation:

Data given:

moles of S $O_{2}$ = 11.5 moles

moles of $H_{2} S_{} O_{4}$ = ?

Moles of $O_{2}$ needed =?

balanced equation with states of matter =?

Balanced chemical reaction under STP condition is given as:

2S $O_{2}$ (g) + $O_{2}$ (g) + 2 $H_{2}$ O (l) ⇒ $H_{2} S_{} O_{4}$

From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:

so, from 11.5 moles of S $O_{2}$ , x moles of $H_{2} S_{} O_{4}$ is formed

$\frac{1}{2} =\frac{x}{11.5}$

2x = 11.5

x = 5.75 moles of sulphuric acid formed.

From the balanced reaction 1 mole of oxygen reacted to form 1 mole of sulphuric acid.

when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.

7 0

3 years ago

Calculate the molarity of the two solutions. The first solution contains 0.550 mol of NaOH in 1.40 L of solution.

olya-2409 [2.1K]

Answer:

0.393 mol/L.

Explanation:

The following data were obtained from the question:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the molarity of the NaOH solution as follow:

Number of mole of NaOH = 0.550 mol

Volume of solution = 1.40 L

Molarity of NaOH =.?

Molarity = mole / Volume

Molarity of NaOH = 0.55 / 1.4

Molarity of NaOH = 0.393 mol/L

Thus, the molarity of the NaOH solution is 0.393 mol/L.

6 0

3 years ago

Which of the following describes a property of water that helps sustain marine life forms?

Mariana [72]

Answer:

Open spaces in water's solid structure makes its solid state less dense than its liquid state.

Explanation:

Water unlike other liquids is special. It contracts when cooled, down to a temperature of 4°C but thereafter begins to expand as it reaches 0°C and turns into ice.
This property is useful for the preservation of marine life in very cold temperatures. During winter, the surface water in water lakes and rivers starts cooling. Upon reaching the temperature of 4°C, the surface water descends to the bottom as it denser.
This help in the maintenance of temperature of the water at the bottom at 4°C. It is in this layer that marine life is sustained.

4 0

3 years ago

When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

8 0

3 years ago