-2 = - x + x^2 -4 => x^2 - x - 4 + 2 = 0
x^2 - x - 2 = 0
a is the coefficient of x^2 => a = 1
b is the coefficient of x => b = - 1
c is the constant term => c = - 2
quadratic equation: [- b +/- √(b^2 - 4ac) ] / 2a =
= { 1 +/- √[ (-1)^2 - 4(1)(-2)] } / (2(1) = { 1 +/- √ (1 + 8) } / 2 = {1 +/- √9} / 2 =
= { 1 +/- 3} / 2
X=numerator
y=denominator
the sum of numerator and denominator=x+y
we suggest this system of equations:
y=x-3
(x+5) / (y+5)=5/6
we solve this system of equation by substitution method.
(x+5) / (x-3+5)=5/6
(x+5) / (x+2)=5/6
6(x+5)=5(x+2)
6x+30=5x+10
6x-5x=10-30
x=-20
y=x-3=-20-3=-23
Teh sum of the numerator an denominator=-20+(-23)=-43
Answer: -43
Answer:
C.(3|-4)
Step-by-step explanation:
Answer:
1456
Step-by-step explanation:
56x2x13
56x26
1456
-0.127
-0.12
0.20
0.33
45/10
I think that is right
