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Elodia [21]
3 years ago
6

Point Q is plotted on the coordinate grid. Point P is at (20, −30). Point R is vertically above point Q. It is at the same dista

nce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q?
On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 40, negative 30.

Point R is at (−40, 30), a distance of 60 units from point Q
Point R is at (−40, −10), a distance of 20 units from point Q
Point R is at (−40, −30), a distance of 60 units from point Q
Point R is at (−40, 10), a distance of 20 units from point Q
Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

Point R is at (−40, −10), a distance of 20 units from point Q

Step-by-step explanation:

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Please help with this postulate! :)
atroni [7]

Answer:

  • C. ASA postulate

Step-by-step explanation:

<u>We observe two angles and the included side of ABC are congruent to two angles and the included side of DBE:</u>

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This is called ASA

7 0
2 years ago
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#4 find the value of x round answer to the nearest tenth
AnnyKZ [126]

Answer:

Step-by-step explanation:

Since this is a right angled triangle:

tan(∅) = opposite side/adjacent side

In this triangle:

tan(25°) = x/19

x = 8. 86 ≅ 8.9

6 0
3 years ago
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) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

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8 0
3 years ago
Someone please help! find x round to the nearest tenth! trigonometry!​
TEA [102]

Answer:

<h2>x = 745.5 ft</h2>

Step-by-step explanation:

Look at the picture.

Use sine:

sine=\dfrac{opposite}{hypotenuse}

We have a measure of the angle and length of the opposite:

\alpha=28^o,\ opposite=350\ ft

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Substitute:

\dfrac{350}{x}=0.4695

\dfrac{350}{x}=\dfrac{4695}{10000}            <em>cross multiply</em>

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x=\dfrac{3500000}{4695}\to x\approx745.5

5 0
3 years ago
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LuckyWell [14K]

Answer:

50 in ^3

Step-by-step explanation:

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V = 50 in ^3

5 0
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