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Elodia [21]
3 years ago
6

Point Q is plotted on the coordinate grid. Point P is at (20, −30). Point R is vertically above point Q. It is at the same dista

nce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q?
On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 40, negative 30.

Point R is at (−40, 30), a distance of 60 units from point Q
Point R is at (−40, −10), a distance of 20 units from point Q
Point R is at (−40, −30), a distance of 60 units from point Q
Point R is at (−40, 10), a distance of 20 units from point Q
Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

Point R is at (−40, −10), a distance of 20 units from point Q

Step-by-step explanation:

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Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

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Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

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Also, the slope of the line is -2.

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$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

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Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

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Hence, slope-intercept form of equation is given as y=-2x-2.

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Step-by-step explanation:

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