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Wittaler [7]
3 years ago
5

How to solve this (2x³+11x³+11x-4)cm³ by its height (x+4)cm. what is the area ?​

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

Given

V = 2x³-11x²+13x-4 cm³

A = (x-4)

H = ?

We all know that the formula in finding the volume of a rectangular prism is

And to determine the area of a rectangle is

Therefore to put into conclusion

We are finding the height of the rectangular prism, so we have to transpose the variable of height to the left.

Put the variables in the formula

In this case, we can able to use the Synthetic Division Method, but it doesn't apply for all equations.

The divisor must have a constant of only one, nothing else

The exponent of the linear term of the divisor is only one, nothing else.

SOLUTION USING SYNTHETIC DIVISION IS IN THE PHOTO

The height of the rectangular prism is

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Which expression represents the volume, in cubic
muminat

Given:

The composite figure.

To find:

The volume of the given composite figure.

Solution:

Given composite figure contains a cuboid and a pyramid.

Length, breadth and height of the cuboid are 8, 6 and 4 respectively.

Volume of a cuboid is

V_1=length\times breadth\times height

V_1=(8)(6)(4)

Length and breadth of the pyramid is same as the cuboid, i.e., 8 and 6 respectively.

Height of pyramid = 10 - 4 = 6

Volume of a pyramid is

V_2=\dfrac{1}{3}\times length\times breadth\times height

V_2=(\dfrac{1}{3})(8)(6)(6)

The volume of composite figure is

V=V_1+V_2

V=(8)(6)(4)+(\dfrac{1}{3})(8)(6)(6)

It can be written as

V=(\dfrac{1}{3})(8)(6)(6)+(8)(6)(4)

Therefore, the correct option is A.

3 0
3 years ago
Factor completely x2 + 20x − 36. (1 point)
Serggg [28]

Consider the form x^2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 36 and whose sum is 20.

2, 18

Write the factored form using these integers.

(x+2)(x+18)

4 0
3 years ago
Given the domain values {-3, 0, 3} what is the range for the equation f(x) = −5x + 2? Question options: {-3, 0, 3} {-6, 2, 6} {-
Fynjy0 [20]

The range is the set of all possible output, as you feed the function with all possible inputs. Since our inputs (domain) are -3, 0, 3, our outputs are

f(-3) = 15+2 = 17\\f(0)=0+2 = 2\\f(3) = -15+2 = -13

So, the range is

\{-13, 2, 17\}

5 0
3 years ago
(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

7 0
3 years ago
I finished question 1 but I could use some help on the others​
Eddi Din [679]

Answer:

With the first four questions, all you need to do is find a value of x that gives you a zero value in any one of those brackets.  Let's do it.

You said you finished 1, so let's skip it.

I can't give you a full answer for question 2, because you didn't capture the entire expression in the screenshot.  I can see that the values 3 and 0.125 would give zero values, but I can't tell you the last.

For question three, we need to find x values where either 9x + 3 = 0, or x² - 9 = 0.  There are three values that meet those conditions.  You can solve it just by assigning a zero value and solving for x:

9x + 3 = 0\\3x + 1 = 0\\3x = -1\\x = -1/3

For the second term actually has two solutions, because a squaring a number also causes negatives to be converted to positives.  Another way of seeing this is to notice that the second term is actually a difference of squares:

p(x) = (9x + 3)(x^2 - 9)\\= (9x + 3)(x + 3)(x - 3)

so in this case x could be -1/3, -3, or 3 to give a zero value.

For question four, you can only get a zero if you use imaginary numbers, as no real number can be squared to give you a negative.  So the only answers to that are 5i, or -5i.

With questions five six seven and eight, we just need to make exceptions for zero denominators, so:

For question 5, you can x can be any real number except -4, 2 and 7

For 6, x can be anything but 3, 1/8th or 5

for 7, We again have that difference of squares, so the actual denominator is (9x + 3)(x + 9)(x - 9), meaning x can be anything but -1/3, -9, or 9

And finally for question 8, we again have a squaring, meaning that only an imaginary number will cause division by zero, meaning x can't be 5i or -5i.

7 0
3 years ago
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