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Kaylis [27]
2 years ago
10

A company sells sneakers and has a revenue that can be represented by the function R(s) = 80s – s2, where s represents the numbe

r of pairs of sneakers sold. The sneaker company has a fixed cost of $1,000, and each pair of sneakers costs $25 to manufacture. Which of the following functions represents the profit P(s) of the sneaker company?
P(s) = – s2 + 105s – 1,000
P(s) = – s2 + 55s – 1,000
P(s) = – s2 + 105s + 1,000
P(s) = – s2 + 55s + 1,000
Mathematics
1 answer:
Harman [31]2 years ago
6 0

Answer:

the second one is the answer

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NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

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furthermore, you know that:

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lets call to this integral, the integral Io.

for a general form of I you have In:

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furthermore you use the fact that:

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by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

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false

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Answer:

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