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2 years ago

F(x) = -322 Find f(-2)

Mathematics

1 answer:

serg [7]2 years ago

8 0

Answer:

f ( - 2 ) = - 12

Step-by-step explanation:

f ( - 2 ) = - 3 ( -2 )^2

then you do the exponent first so

- 3 ( 4 )

now you multpily the - 3 and 4

you get - 12

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In-s [12.5K]

The answer is d.subx=0/y=0

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3 years ago

Please help me with this math problem!! Will give brainliest!! :)

Greeley [361]

Answer: -12 but could be wrong

Step-by-step explanation:

I don't know that format but I'm going to take a guess.

x^2 +2x - 8 -(2x+8) then plug in x=2

x^2 + 2x - 8 - 2x - 8

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= 2^2 - 16 = -12

5 0

1 year ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$

Step 3: Find Particular Solution

Substitute in point [Function]: $\displaystyle 18 = \frac{0^2}{16} + C$
Simplify: $\displaystyle 18 = 0 + C$
Add: $\displaystyle 18 = C$
Rewrite: $\displaystyle C = 18$
Substitute in C [Function]: $\displaystyle y = \frac{t^2}{16} + 18$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

4 0

2 years ago

Find the value of x for g(x) = -x + 5 when g(x) = 2.

Lana71 [14]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The length of a rectangle is 3 inches more than its width. the area of the rectangle is 40 square inches. what is the length, in

IceJOKER [234]

Since width is the smaller value, set width=x. That wold mean that length=x+3. Since Area=width*length, 40=x(3+x). Distribute the x to give you 40=3x+x^2. Set the equation equal to 0 giving you x^2+3x-40=0. Factor the equation to give you (x+8)(x-5)=0. Set each factor equal to 0. x+8=0 gives you x=-8 & x=-5 gives you x=5. Since we're working with lengths of objects, it can't be negative. Therefore, your width is 5. To find length, substitute width into the original expression (x+3). Therefore, length is 5+3=8.

4 0

2 years ago

F(x) = -322 Find f(-2)​

F(x) = -322 Find f(-2)