Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
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<em>From table the brown eyes from males = 10</em>
<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male
Answer:
4.6 hours
Step-by-step explanation:
we first need to calculate the total distance he covered and total time taken whole for the journey.
Distance= speed X time
time = Distance/speed
let the total distance be X. he covers 2/5 if the journey first.
2/5 = 0.4
Time = 0.4x/45 hours
the remaining journey is 3/5x
he covers 1/3 X 3/5= 0.2x
time taken = 0.2/90 X hours
the remaining distance = 100× 1.2 = 120km
we add 0.4x + 0.2x to get the fraction he had covered
0.6x.
the remaining distance was X - 0.6x = 0.4 X
thus 120 km represents 0.4x of the journey
we calculate now the value of X
0.4x = 120
X = 300km
Total time taken = 0.4x/45 + 0.2/90 + 1.2 hours
replace X to get time
2.7 hours + 0.7 hours + 1.2 hours
= 4.6 hours
Answer:
r= 15
Step-by-step explanation:
Answer:
The shaded area is 314.2 cm²
Step-by-step explanation:
Here we have the diameter, d₁ of the smaller semicircles as 10 cm
We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;
1 shaded small semicircle and the other is blank
Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm
Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows
Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²
Shaded area = 314.2 cm².
